## Results

### #1. Review the chart excerpt. Which altimeter setting should be used when flying under the base of the Yorkshire CTA over Barnsley to ensure vertical separation from the lower airspace boundary?

### #2. In the image, what do the numbers 1184 with 394 in parenthesis depict?

### #3. What is an isogonal?

### #4. An aircraft is flying with a true airspeed (TAS) of 180kt and a headwind component of 25kt for 2 hours and 25 minutes. What is the total distance flown?

With a 25 kt headwind component, the groundspeed of the aircraft would be 155kt.

155 kt for 2:25 = 375nm

### #5. When variation is nil ...

### #6. The shortest track between two points on the earth is called

### #7. If a pilot changes an altimeter setting from 986hPa to 1013hPa, the altitude indication will:

### #8. On a chart, 12cm represents 60km, what is the scale of the chart?

On a 1:500,000 (or “half-mill”) chart, each centimetre represents an actual distance of 50,000cm – or 500m, 0.5km.

### #9. An aircraft is heading 201° with 12° left drift; variation from the chart is 6°W and the compass correction card indicates 6°E deviation. What is the aircraft's true track?

### #10. A rhumb line

### #11. The Lambert Conformal Conic Projection method used on 1:500,000 scale charts:

### #12. Zero degrees latitude is found

### #13. An aircraft is heading 270° with 7° left drift; variation from the chart is 2°W and the compass correction card indicates 4°E deviation. What is the aircraft's true track?

### #14. True heading is 270°. Magnetic variation is 10° East. What is magnetic heading?

### #15. You plan a flight over Barnsley. By Referencing the 1:500,000 chart, you note that the Yorkshire CTA (A) is above Barnsley. With a QNH of 1006 Hectopascals, the base of the Yorkshire CTA over Barnsley will be at approximately which altitude above mean sea level (AMSL) ?

The Yorkshire CTA is at FL55 (Flight level 55 and above), 5500 feet using standard pressure settings (QNE.)

This is assuming an altimeter subscale setting of 1013 hectopascals.

With the given QNH of 1006 hPa, there is a difference of 7 hPa under the QNE standard; assuming 30 feet per hPa, 30 x 7 = 210, so the base of the CTA would be 5500-210 = 5290 feet altitude.

The question here has been kind enough to remind you that altitude is expressed as above mean sea level.

Height is above ground, and flight levels are assuming a fixed setting of 1013 hPa, irrespective of current meteorological conditions.

### #16. In reference to the earth's magnetic field, Where is dip the greatest?

### #17. Refer to the image with the MEF (Maximum Elevation Figure) circled. Which of the following statements is correct?

### #18. Variation is:

### #19. An aerodrome is marked on a chart with the letters FIG and a Morse code pattern. What does this mean?

### #20. The circled large number 2 with smaller number 6 in the image depicted is a Maximum Elevation Figure (MEF). What defines this?

How an MEF is worked out:

Elevation of obstacle top, above mean sea level: 2424

Possible vertical error: 100

added together = 2524

Raise to the following 100′ level: 2600

MEF: 2^6